8x-[2x-3(x+2)]+4(x+1)=36

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Solution for 8x-[2x-3(x+2)]+4(x+1)=36 equation:


Simplifying
8x + -1[2x + -3(x + 2)] + 4(x + 1) = 36

Reorder the terms:
8x + -1[2x + -3(2 + x)] + 4(x + 1) = 36
8x + -1[2x + (2 * -3 + x * -3)] + 4(x + 1) = 36
8x + -1[2x + (-6 + -3x)] + 4(x + 1) = 36

Reorder the terms:
8x + -1[-6 + 2x + -3x] + 4(x + 1) = 36

Combine like terms: 2x + -3x = -1x
8x + -1[-6 + -1x] + 4(x + 1) = 36
8x + [-6 * -1 + -1x * -1] + 4(x + 1) = 36
8x + [6 + 1x] + 4(x + 1) = 36

Reorder the terms:
8x + 6 + 1x + 4(1 + x) = 36
8x + 6 + 1x + (1 * 4 + x * 4) = 36
8x + 6 + 1x + (4 + 4x) = 36

Reorder the terms:
6 + 4 + 8x + 1x + 4x = 36

Combine like terms: 6 + 4 = 10
10 + 8x + 1x + 4x = 36

Combine like terms: 8x + 1x = 9x
10 + 9x + 4x = 36

Combine like terms: 9x + 4x = 13x
10 + 13x = 36

Solving
10 + 13x = 36

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 13x = 36 + -10

Combine like terms: 10 + -10 = 0
0 + 13x = 36 + -10
13x = 36 + -10

Combine like terms: 36 + -10 = 26
13x = 26

Divide each side by '13'.
x = 2

Simplifying
x = 2

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